Commit 4855ff51 authored by unknown's avatar unknown
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New tests for prepared statements: 

- 'ps_10nestset' uses a "nested set" approach for an employee 
  hierarchy, then does arithmetic on the "salary" field;
  (soon) to be extended by inserts / deletes which imply
  mass updates on the "l"/"r" fields showing the set inclusion,
- 'ps_11bugs' will get (some of ?) those bug DB entries which
  refer to prepared statements, but whose number does not appear
  in a test file comment - so it will also be extended.
parent 9ed05da4

mysql-test/r/ps_10nestset.result

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use test;

drop table if exists personnel;

Warnings:

Note	1051	Unknown table 'personnel'

create table personnel  (

id     INTEGER AUTO_INCREMENT PRIMARY KEY,

emp    CHAR(10) NOT NULL,

salary DECIMAL(6,2) NOT NULL,

l INTEGER NOT NULL,

r INTEGER NOT NULL);

prepare st_ins from 'insert into personnel set emp = ?, salary = ?, l = ?, r = ?';

set @arg_nam= 'Jerry';

set @arg_sal= 1000;

set @arg_l= 1;

set @arg_r= 12;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Bert';

set @arg_sal=  900;

set @arg_l= 2;

set @arg_r=  3;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Chuck';

set @arg_sal=  900;

set @arg_l= 4;

set @arg_r= 11;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Donna';

set @arg_sal=  800;

set @arg_l= 5;

set @arg_r=  6;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Eddie';

set @arg_sal=  700;

set @arg_l= 7;

set @arg_r=  8;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Fred';

set @arg_sal=  600;

set @arg_l= 9;

set @arg_r= 10;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

select * from personnel;

id	emp	salary	l	r

1	Jerry	1000.00	1	12

2	Bert	900.00	2	3

3	Chuck	900.00	4	11

4	Donna	800.00	5	6

5	Eddie	700.00	7	8

6	Fred	600.00	9	10

prepare st_raise_base from 'update personnel set salary = salary * ( 1 + ? ) where r - l = 1';

prepare st_raise_mgr  from 'update personnel set salary = salary + ? where r - l > 1';

set @arg_percent= .10;

set @arg_amount= 100;

execute st_raise_base using @arg_percent;

execute st_raise_mgr  using @arg_amount;

execute st_raise_base using @arg_percent;

execute st_raise_mgr  using @arg_amount;

execute st_raise_base using @arg_percent;

execute st_raise_mgr  using @arg_amount;

select * from personnel;

id	emp	salary	l	r

1	Jerry	1300.00	1	12

2	Bert	1197.90	2	3

3	Chuck	1200.00	4	11

4	Donna	1064.80	5	6

5	Eddie	931.70	7	8

6	Fred	798.60	9	10

drop table personnel;

mysql-test/r/ps_11bugs.result

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use test;

drop table if exists test_select;

Warnings:

Note	1051	Unknown table 'test_select'

CREATE TABLE test_select(session_id  char(9) NOT NULL);

INSERT INTO test_select VALUES ("abc");

SELECT * FROM test_select;

session_id

abc

prepare st_1180 from 'SELECT * FROM test_select WHERE ?="1111" and session_id = "abc"';

set @arg1= 'abc';

execute st_1180 using @arg1;

session_id

set @arg1= '1111';

execute st_1180 using @arg1;

session_id

abc

set @arg1= 'abc';

execute st_1180 using @arg1;

session_id

drop table test_select;

mysql-test/t/ps_10nestset.test

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###############################################

#                                             #

#   Prepared Statements test on               #

#   "nested sets" representing hierarchies    #

#                                             #

###############################################



# Source: http://kris.koehntopp.de/artikel/sql-self-references (dated 1999)

# Source: http://dbmsmag.com/9603d06.html (dated 1996)



use test;



drop table if exists personnel;



# "Nested Set": This table represents an employee list with a hierarchy tree.

# The tree is not modeled by "parent" links but rather by showing the "left"

# and "right" border of any person's "region". By convention, "l" < "r".

# As it is a tree, these "regions" of two persons A and B are either disjoint,

# or A's region is completely contained in B's (B is A's boss), or vice versa.

# See the references for more info.



create table personnel  (

  id     INTEGER AUTO_INCREMENT PRIMARY KEY,

  emp    CHAR(10) NOT NULL,

  salary DECIMAL(6,2) NOT NULL,

  l INTEGER NOT NULL,

  r INTEGER NOT NULL);



prepare st_ins from 'insert into personnel set emp = ?, salary = ?, l = ?, r = ?';



# Initial employee list:

# Jerry ( Bert ( ) Chuck ( Donna ( ) Eddie ( ) Fred ( ) ) )

set @arg_nam= 'Jerry'; set @arg_sal= 1000; set @arg_l= 1; set @arg_r= 12;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Bert';  set @arg_sal=  900; set @arg_l= 2; set @arg_r=  3;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Chuck'; set @arg_sal=  900; set @arg_l= 4; set @arg_r= 11;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Donna'; set @arg_sal=  800; set @arg_l= 5; set @arg_r=  6;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Eddie'; set @arg_sal=  700; set @arg_l= 7; set @arg_r=  8;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;

set @arg_nam= 'Fred';  set @arg_sal=  600; set @arg_l= 9; set @arg_r= 10;

execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;



select * from personnel;



# Three successive raises, each one is 100 units for managers, 10 percent for others.

prepare st_raise_base from 'update personnel set salary = salary * ( 1 + ? ) where r - l = 1';

prepare st_raise_mgr  from 'update personnel set salary = salary + ? where r - l > 1';

let $1= 3;

set @arg_percent= .10;

set @arg_amount= 100;

while ($1)

{

  execute st_raise_base using @arg_percent;

  execute st_raise_mgr  using @arg_amount;

  dec $1;

}



select * from personnel;



drop table personnel;

mysql-test/t/ps_11bugs.test

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###############################################

#                                             #

#   Prepared Statements                       #

#   re-testing bug DB entries                 #

#                                             #

###############################################



use test;



# bug#1180: optimized away part of WHERE clause cause incorect prepared satatement results



drop table if exists test_select;



CREATE TABLE test_select(session_id  char(9) NOT NULL);

INSERT INTO test_select VALUES ("abc");

SELECT * FROM test_select;



prepare st_1180 from 'SELECT * FROM test_select WHERE ?="1111" and session_id = "abc"';



# Must not find a row

set @arg1= 'abc';

execute st_1180 using @arg1;



# Now, it should find one row

set @arg1= '1111';

execute st_1180 using @arg1;



# Back to non-matching

set @arg1= 'abc';

execute st_1180 using @arg1;



drop table test_select;